Solution:
The time taken to fall through height \(h\) from rest under gravity is \(t = \sqrt{\frac{2h}{g}}\). Since \(t \propto \sqrt{h}\), the ratio of times for heights \(a\) and \(b\) is \(\sqrt{a} : \sqrt{b}\).
Two bodies of different masses \(m_a\) and \(m_b\) are dropped from two different heights, viz, an and b. The ratio of time taken by the two to drop through these distances is :
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