Time for Parrot to Cross Train – Rankers Physics
Topic: Kinematics
Subtopic: Relative Motion in One Dimension

Time for Parrot to Cross Train

A train of \(150\text{ metre}\) length is going towards north direction at a speed of \(10\text{ m/s}\). A parrot flies at the speed of \(5\text{ m/s}\) towards south direction parallel to the railways track. The time taken by the parrot to cross the train is:

(1988)

\(12\text{ sec}\)
\(8\text{ sec}\)
\(15\text{ sec}\)
\(10\text{ sec}\)

Solution:

Concept: Relative velocity for objects moving in opposite directions.
Length of train \(L = 150\text{ m}\)).
Speed of train \(v_T = 10\text{ m/s}\)). Speed of parrot \(v_P = 5\text{ m/s}\)).
Since they move in opposite directions, their relative speed is \(v_{rel} = v_T + v_P = 10 + 5 = 15\text{ m/s}\).
Time taken to cross: \(t = L/v_{rel} = 150/15 = 10\text{ s}\).

Leave a Reply

Your email address will not be published. Required fields are marked *