Height of Tower in Vertical Throw – Rankers Physics
Topic: Kinematics
Subtopic: Motion Under Gravity

Height of Tower in Vertical Throw

A ball is thrown vertically downward with a velocity of \(20\text{ m/s}\) from the top of a tower. It hits the ground after some time with a velocity of \(80\text{ m/s}\). The height of the tower is : \((g = 10\text{ m/s}^2)\)

(2020)

340 m
320 m
300 m
360 m

Solution:

Concept: Equations of motion under gravity.
Formula: \(v^2 = u^2 + 2gh\).
Solution: Given \(u = 20\text{ m/s}\,\text{ }v = 80\text{ m/s}\,\text{ }g = 10\text{ m/s}^2\). Substituting these values: \(80^2 = 20^2 + 2(10)h\). \(6400 = 400 + 20h\). \(6000 = 20h\) => \(h = 300\text{ m}\).

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