(2022)
Solution:
Concept: Galileo's law of odd numbers for free fall.
Formula: Distance in \(n^{text{th}}\) second is \(S_n = \frac{g}{2}(2n - 1)\).
Solution: \(S_1:S_2:S_3:S_4 = (2(1)-1):(2(2)-1):(2(3)-1):(2(4)-1) = 1:3:5:7\).
The ratio of the distance traveled by a freely falling body in the \(1^{text{st}}\,\text{ }2^{text{nd}}\,\text{ }3^{text{rd}}\) and \(4^{text{th}}\) second:
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