Solution:
For an orbiting satellite, Potential Energy \(U = -\frac{GMm}{r}\), Kinetic Energy \(K = \frac{GMm}{2r}\), and Total Energy \(E = -\frac{GMm}{2r}\). This shows that \(U = 2E\).
For an orbiting satellite, Potential Energy \(U = -\frac{GMm}{r}\), Kinetic Energy \(K = \frac{GMm}{2r}\), and Total Energy \(E = -\frac{GMm}{2r}\). This shows that \(U = 2E\).
Leave a Reply