Solution:
Since the field is uniform, potential varies linearly with height. Potential difference at \(5.0\text{ m}\) is \(\Delta V = 4 \times \frac{5.0}{10} = 2\text{ J/kg}\. Work done is \(W = m \Delta V = 2.0 \times 2 = 4.0\text{ J}\).
Since the field is uniform, potential varies linearly with height. Potential difference at \(5.0\text{ m}\) is \(\Delta V = 4 \times \frac{5.0}{10} = 2\text{ J/kg}\. Work done is \(W = m \Delta V = 2.0 \times 2 = 4.0\text{ J}\).
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