Rankers Physics
Topic: Gravitation
Subtopic: Gravitational Potential Energy

For a satellite escape velocity is $11\text{ km/s}$. If the satellite is launched at an angle of $60^{\circ}$ with the vertical, then escape velocity will be:

(1989)

$11\text{ km/s}$
$11\sqrt{3}\text{ km/s}$
$\frac{11}{\sqrt{3}}\text{ km/s}$
$33\text{ km/s}$

Solution:

The escape velocity formula depends solely on the gravitational potential and mass/radius of the body. It is independent of the angle at which the object is launched.

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