Acceleration due to gravity on a spherical planet

A spherical planet has a mass $M_P$ and diameter $D_P$. A particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity, equal to:

(2012 Pre)

$\frac{4GM_P}{D_P^2}$

$\frac{GM_Pm}{D_P^2}$

$\frac{GM_P}{D_P^2}$

$\frac{4GM_Pm}{D_P^2}$

Solution:

Acceleration due to gravity is given by $g = \frac{GM_P}{R_P^2}$. Substituting the radius as half of the diameter, $R_P = \frac{D_P}{2}$, we get $g = \frac{GM_P}{(D_P/2)^2} = \frac{4GM_P}{D_P^2}$.

Acceleration due to gravity on a spherical planet

Solution:

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