Solution:
By conservation of energy, \(v_{\infty} = \sqrt{v^2 - v_{\text{esc}}^2} = \sqrt{(2v_{\text{esc}})^2 - v_{\text{esc}}^2} = v_{\text{esc}}\sqrt{3} = 11.2\sqrt{3} \text{km/s}\).
The escape velocity of a body on the earth surface is 11.2 km/s. If the same body is projected upward with velocity 22.4 km/s, the velocity of this body at infinite distance from the centre of the earth will be
Leave a Reply