Four charges are placed on the circumference of a circle of radius R, 90° apart as shown in the figure . The electric field strength at the centre of the circle is
\frac{1}{4\pi\varepsilon_{0}}\frac{2\sqrt{5}Q}{R^{2}}, making angle tan^{-1}2 with the -ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{2\sqrt{5}Q}{R^{2}}, making angle tan^{-1}2 with the +ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{4\sqrt{2}Q}{R^{2}}, making angle tan^{-1}\frac{1}{2} with the -ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{4\sqrt{2}Q}{R^{2}}, making angle tan^{-1}\frac{1}{2} with the +ve axis
No solution provided for this question.
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