Reason (R): The electrostatic potential is always same from center to surface of a conducting shell.
Solution:
In electrostatic equilibrium, the electric field inside a conductor is zero \( (\vec{E} = \vec{0}) \). Since \( \vec{E} = -\nabla V \), if \( \vec{E} = \vec{0} \), the potential \( V \) must be constant throughout the conductor, from center to surface. Thus (A) and (R) are true, and (R) explains (A).
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