Column A: A. Charge outside a closed gaussian surface B. Charge \(q\) inside a closed gaussian surface C. Infinite plane sheet of charge D. Field outside a charged conducting sphere
Column B: (P) \(\oint \vec{E} \cdot d\vec{A} = \frac{q}{epsilon_0}\) (Q) \(E = \frac{\sigma}{2\epsilon_0}\) (R) \(E = \frac{KQ}{r^2}\) (S) Net flux is zero
Solution:
A charge outside a closed surface contributes zero net flux (A-S). Gauss's law states that for an enclosed charge \(q\), the net flux is \(\frac{q}{\epsilon_0}\) (B-P). The electric field due to an infinite plane sheet is \(E = \frac{\sigma}{2\epsilon_0}\) (C-Q). For a charged conducting sphere, the external field is \(E = \frac{KQ}{r^2}\) (D-R).
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