Solution:
Initially, \( F = k \frac{q^2}{r^2}\). When 50% of the charge of one sphere is transferred to the other, the charges become \(0.5q\) and
\(1.5q\). The new force is \(F' = k \frac{(0.5q)(1.5q)}{r^2} = 0.75 F = \frac{3}{4}F\).
Force between two identical spheres charged with same charge is \(F \). If 50% charge of one sphere is transferred to the other sphere then the new force will be:
Leave a Reply