Charge to Mass Ratio for No Net Force – Rankers Physics
Topic: Electrostatics
Subtopic: Coulomb's Law

Charge to Mass Ratio for No Net Force

Two particle of equal mass m and charge q are placed at a distance of 16 cm. They do not experience any force. The value of \( \frac{q}{m} \) is:
1
\( \sqrt{\frac{\pi \varepsilon_0}{G}} \)
\( \sqrt{\frac{G}{4 \pi \varepsilon_0}} \)
\( \sqrt{4 \pi \varepsilon_0 G} \)

Solution:

For no net force, electrostatic force must equal gravitational force: \( \frac{q^2}{4 \pi \varepsilon_0 r^2} = \frac{G m^2}{r^2} \). Rearranging this formula yields \( \frac{q^2}{m^2} = 4 \pi \varepsilon_0 G \Rightarrow \frac{q}{m} = \sqrt{4 \pi \varepsilon_0 G} \).

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