Solution:
The displacement current is equal to the conduction current, which is \(I_d = \frac{dq}{dt}\). Since \(q = CV = C V_0 \sin\omega t\), differentiating with respect to time gives \(I_d = V_0 \omega C \cos\omega t\).
A capacitor of capacitance \(C\), is connected across an ac source of voltage \(V\), given by \(V = V_0\sin\omega t\). The displacement current between the plates of the capacitor, would then be given by
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