NEET Physics Question - Electromagnetic Induction

Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate 15.0 A/s the emf in coil 1 in 25.0 mV, when coil 2 has no current and coil 1 has a current of 3.6 A, the flux linkage in coil 2 is:

16 mWb

10 mWb

4.00 mWb

6.00 mWb

Solution:

Based on the problem in your editor, here is the solution in 3 lines without using the $ symbol:

Find Mutual Inductance (M): M = Induced EMF / (rate of change of current) = 25.0 mV / 15.0 A/s = 1.667 mH.
Calculate Flux Linkage: Flux = M × Current = 1.667 mH × 3.6 A = 6.00 mWb.
Result: The flux linkage in coil 2 is 6.00 mWb (Option 4).

Rankers Physics

Solution:

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