Magnetic field from flux and angle – Rankers Physics
Topic: Electromagnetic Induction
Subtopic: Magnetic Flux

Magnetic field from flux and angle

A flux of \(10^{-3}\text{ Wb}\) passes through a strip having an area \(A = 0.02\text{ m}^2\). The plane of the strip is at an angle of \(60^\circ\) to the direction of a uniform field \(B\). The value of \(B\) is:
\(0.1\text{ T}\)
\(0.058\text{ T}\)
\(4.0\text{ mT}\)
None of the above

Solution:

The magnetic flux through the surface is given by \(\phi = B A \sin\theta\). Substituting \(\phi = 10^{-3}\text{ Wb}\), \(A = 0.02\text{ m}^2\), and \(\theta = 60^\circ\), we get \(B = \frac{10^{-3}}{0.02 \times \sin 60^\circ} \approx 0.058\text{ T}\).

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