Solution:
Change in flux \(\Delta \Phi = 2NBA = 2 \times 200 \times 0.3 \times (70 \times 10^{-4}) = 0.84\text{ Wb}\). Induced EMF is \(e = \frac{\Delta \Phi}{\Delta t} = \frac{0.84}{0.1} = 8.4\text{ V}\).
A coil has 200 turns and area of \(70\text{ cm}^2\). The magnetic field perpendicular to the plane of the coil is \(0.3\text{ Wb m}^{-2}\) and takes \(0.1\text{ s}\) to rotate through \(180^\circ\). The value of the induced E.M.F. will be:
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