Solution:
Resistance is inversely proportional to the square of the diameter: \(R = \frac{1}{d^2}\). Since the diameter is tripled, the resistance becomes \(\frac{R}{9} = \frac{81}{9} = 9 \Omega\).
A certain wire \(A\) has resistance \(81 \Omega\). The resistance of another wire \(B\) of same material and equal length but of diameter thrice the diameter of \(A\) will be
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