Kinematics of Circular Motion - NEET Physics Chapterwise MCQs & PYQs

NEET Kinematics of Circular Motion MCQs & PYQs

Kinematics of circular motion is important for preparation of NEET, JEE Mains, JEE Advance , CUET and other exams in which Physics is asked

Question 11:

easy

Assertion (A): Average angular velocity is a scalar quantity.


Reason (R): Large angular displacements \( (\Delta \theta) \) is a scalar.


 

Instantaneous angular velocity \( \vec{\omega} \) is a vector. However, finite angular displacement \( \Delta \theta \) is not a vector, but a scalar, as stated in Reason (R). Therefore, if average angular velocity is defined as the scalar \( \Delta \theta / \Delta t \), then Assertion (A) is considered true. In this context, both (A) and (R) are true, and (R) provides the explanation for (A).

Question 12:

easy

Assertion (A): Angular velocity of the seconds hand of a watch is \(\frac{\pi}{30}\text{ rad/s}\).


Reason (R): Angular velocity is equal to \(\frac{2\pi}{\text{T}}\) where \(\text{T}\) is the time period.


 

Angular velocity \(\omega = \frac{2\pi}{\text{T}}\). For a seconds hand, \(\text{T} = 60\text{ s}\). Thus, \(\omega = \frac{2\pi}{60} = \frac{\pi}{30}\text{ rad/s}\). Both assertion and reason are true, and the reason correctly explains the assertion.

Question 13:

easy

The angular speed of a fly wheel moving with uniform angular acceleration changes from $1200\text{ rpm}$ to $3120\text{ rpm}$ in $16\text{ seconds}$. The angular acceleration in $\text{rad/s}^2$ is:

(2022)

Concept: Definition of angular acceleration. Formula: $\alpha = \frac{\omega_2 - \omega_1}{t}$. Solution: Converting rpm to rad/s and substituting values gives $\alpha = 4\pi\text{ rad/s}^2$.

Question 14:

easy

The angular speed of the wheel of a vehicle is increased from $360\text{ rpm}$ to $1200\text{ rpm}$ in $14\text{ second}$. Its angular acceleration is.

(2020-Covid)

Concept: Kinematic equation for angular motion. Formula: $\alpha = \frac{\Delta \omega}{t}$. Solution: $\omega_1 = 12\pi$, $\omega_2 = 40\pi$, yielding $\alpha = \frac{28\pi}{14} = 2\pi\text{ rad/s}^2$.

Question 15:

easy

A wheel has angular acceleration of $3.0\text{ rad/sec}^2$ and an initial angular speed of $2.00\text{ rad/sec}$. In a time of $2\text{ sec}$ it has rotated through an angle (in radian) of:

(2007)

Concept: Rotational kinematics equation. Formula: $\theta = \omega_0 t + \frac{1}{2}\alpha t^2$. Solution: $\theta = (2.0)(2) + \frac{1}{2}(3.0)(2)^2 = 4 + 6 = 10\text{ radians}$.