Centripetal Force from Kinetic Energy – Rankers Physics
Topic: Circular Motion
Subtopic: Kinematics of Circular Motion

Centripetal Force from Kinetic Energy

The kinetic energy \((K)\) of particle moving along a circle of radius \(R\) depends upon the distance covered \(S\) and is given by \(K = aS\) where \(a\) is a constant. Then the centripetal force acting on the particle is:
\(\frac{aS}{R}\)
\(\frac{2(aS)^2}{R}\)
\(\frac{aS^2}{R}\)
\(\frac{2aS}{R}\)

Solution:

Kinetic energy is \(K = \frac{1}{2}mv^2 = aS\). Centripetal force is \(F_c = \frac{mv^2}{R}\) ( Since \(mv^2 = 2aS\), we get \(F_c = \frac{2aS}{R}\).

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