Angular Velocity and Radius Vector Cross Product

For a body angular velocity $\vec{\omega} = \hat{i} - 2\hat{j} + 3\hat{k}$ and radius vector is $\vec{r} = \hat{i} + \hat{j} + \hat{k}$ then its velocity is:

(1999)

$-5\hat{i} + 2\hat{j} + 3\hat{k}$

$-5\hat{i} + 2\hat{j} - 3\hat{k}$

$-5\hat{i} - 2\hat{j} + 3\hat{k}$

$-5\hat{i} - 2\hat{j} - 3\hat{k}$

Solution:

Velocity is given by $\vec{v} = \vec{\omega} \times \vec{r}$. Evaluating the cross-product determinant yields $-5\hat{i} + 2\hat{j} + 3\hat{k}$.

Angular Velocity and Radius Vector Cross Product

Solution:

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