(2016-I)
Solution:
Work done by tangential force $W = (ma_t)s = \Delta K$, where distance $s = 4\pi r = 4 \times \pi \times 0.064 \text{ m}$. Substituting values gives $a_t = 0.1 \text{ m/s}^2$.
(2016-I)
Work done by tangential force $W = (ma_t)s = \Delta K$, where distance $s = 4\pi r = 4 \times \pi \times 0.064 \text{ m}$. Substituting values gives $a_t = 0.1 \text{ m/s}^2$.
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