Solution:
The maximum safe speed on an unbanked circular curve is \(v_{\max} = \sqrt{\mu g r}\). Substituting the values, \(v_{\max} = \sqrt{0.75 \times 10 \times 30} = \sqrt{225} = 15\text{ m/s}\).
An unbanked road has a radius of curvature equal to \(30\text{ m}\). The maximum speed at which a car can make a turn if the coefficient of friction is \(0.75\), is
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