Reason (R): Electric field is zero outside outer shell when inner shell is grounded.
Solution:
A: True. For inner charged, outer grounded, \(C_1 = 4\pi\epsilon_0 \frac{ab}{b-a}\). For inner grounded, outer charged, \(C_2 = 4\pi\epsilon_0 \frac{b^2}{b-a}\). Since \(b>a\), \(C_1 < C_2\).\nR: False. If the outer shell is given charge, there will be a net charge creating an external electric field.\nTherefore, (A) is true and (R) is false.
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