NEET Physics Question - Capacitors - Parallel Plate Capacitor

Assertion (A): If separation between plates of a parallel plate isolated charged capacitor is increased, its energy stored will be increased.

Reason (R): Work done to separate the plates get converted in electrostatic potential energy.

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

(A) is true but (R) is false

Both (A) and (R) are false

Solution:

For an isolated capacitor, charge (Q) is constant. Energy stored is \(U = \frac{Q^2}{2C}\). If separation (d) increases, capacitance \(C = \frac{\epsilon_0 A}{d}\) decreases. Therefore, (U) increases. This increase in energy comes from the work done by an external agent to separate the plates against attractive electrostatic forces.

Rankers Physics

Energy of Isolated Parallel Plate Capacitor

Solution:

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