Solution:
The energy density of the electric field is given by \(u = \frac{1}{2}\varepsilon_0 E^2\). Thus, the total energy stored is \(U = u \times \text{Volume} = \frac{1}{2}\varepsilon_0 E^2 Ad\).
A parallel plate capacitor has a uniform electric field \(\vec{E}\) in the space between the plates. If the distance between the plates is \(d\) and the area of each plate is \(A\), the energy stored in the capacitor is (\(\varepsilon_0\) = permittivity of free space)
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