Solution:
Current is maximum at resonance, where \(\omega = \frac{1}{\sqrt{LC}}\). Solving for \(C\): \(C = \frac{1}{\omega^2 L} = \frac{1}{(100)^2 \times 50 \times 10^{-3}} = 2 \times 10^{-3}\)⇒ C = 2 mF.
The value of capacitance \(C\) in an LCR series circuit with inductance \(L = 50\) mH, connected with a voltage source of angular frequency \(100\) rad/s so that current in the circuit becomes maximum, is:
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