Nucleus: Practice Problem & Solution
Assertion (A): \( \text{Fe}^{56} \) nucleus is more stable than \( \text{U}^{235} \) nucleus. Reason (R): Binding energy of \( \text{Fe}^{56} \) nucleus is more than binding energy of \( \text{U}^{235} \).
Solution Explained:
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
\( \text{Fe}^{56} \) has the highest binding energy per nucleon, making it the most stable. So (A) is true. The total binding energy of \( \text{U}^{235} \) is much higher than \( \text{Fe}^{56} \) due to its larger number of nucleons. Thus (R) is false.
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