Nucleus: Practice Problem & Solution
The nucleus $_{6}C^{12}$ absorbs an energetic neutron and emits a beta-particle ($\beta$). The resulting nucleus is (1990)
Solution Explained:
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
Absorption of a neutron: $_{6}C^{12} + _{0}n^{1} \rightarrow _{6}C^{13}$. Subsequent $\beta$ decay increases the atomic number by 1: $_{6}C^{13} \rightarrow _{7}N^{13} + _{-1}e^{0} + \bar{\nu}$. The resulting nucleus is $_{7}N^{13}$.
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