Nucleus: Practice Problem & Solution
In the nuclear decay given below: $^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y \rightarrow ^{A-4}_{Z-1}B^* \rightarrow ^{A-4}_{Z-1}B$, the particles emitted in the sequence are: (2009)
Solution Explained:
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
Step 1: Z increases by 1, A is constant -> $\beta$ emission. Step 2: Z decreases by 2, A decreases by 4 -> $\alpha$ emission. Step 3: Excited state ($B^*$) to ground state ($B$) with no change in Z or A -> $\gamma$ emission. The sequence is $\beta, \alpha, \gamma$.
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