Rankers Physics

Nucleus: Practice Problem & Solution

In the nucleus of $ _{11}Na^{23} $, the number of protons, neutrons and electrons are (1991)
$ 11, 12, 0 $
$ 23, 12, 11 $
$ 12, 11, 0 $
$ 23, 11, 12 $

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

For a nucleus represented as $ _{Z}X^{A} $, the number of protons is $ Z = 11 $. The number of neutrons is $ A - Z = 23 - 11 = 12 $. Since it is a nucleus, there are no electrons present, so electrons = 0.

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