Rankers Physics

Atomic Structure: Practice Problem & Solution

The energy of a hydrogen atom in its ground state is $-13.6 eV$. The energy of the level corresponding to the quantum number $n = 2$ in the hydrogen atom is (1996)
$-0.54 eV$
$-3.4 eV$
$-2.72 eV$
$-0.85 eV$

Solution Explained:

To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:

The energy of an electron in the nth orbit is $E_n = \frac{-13.6}{n^2} eV$. For $n=2$, the energy is $E_2 = \frac{-13.6}{4} = -3.4 eV$.

Leave a Reply

Your email address will not be published. Required fields are marked *