Rankers Physics

Atomic Structure: Practice Problem & Solution

The total energy of an electron in the $n^{th}$ stationary orbit of the hydrogen atom can be obtained by. (2020-Covid)
$E_n = -\frac{13.6}{n^2} eV$
$E_n = -\frac{1.36}{n^2} eV$
$E_n = -13.6 \times n^2 eV$
$E_n = \frac{13.6}{n^2} eV$

Solution Explained:

To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:

According to Bohr's theory, the total energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by the formula $E_n = -\frac{13.6}{n^2} eV$.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Let $T_1$ and $T_2$ be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr's model of an atom, the ratio $T_1 : T_2$ is: (2022)
2. In the Davisson and Germer experiment, the velocity of electrons emitted from the electron gun can be increased by (2011 Pre)
3. Assertion (A): The ratio of wavelength in first transition of lyman series for H atom and He+ atom is exactly equal to four. Reason (R): In all atoms electron revolve around fixed nucleus.  
4. Assertion (A): Penetration power of hard X-ray is more than that of soft X-ray. Reason (R): Hard X-ray is used for engineering purpose while soft X-ray is used for medical purpose.  
5. The nuclei $ _{6}C^{13} $ and $ _{7}N^{14} $ can be described as (1990)