Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

Momentum of photon wavelength $\lambda$ is (1993)
$\frac{h\nu}{c}$
Zero
$\frac{h\nu}{c^2}$
$\frac{h\gamma}{c}$

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

The momentum of a photon is given by $p = \frac{h}{\lambda}$. Since $c = \nu \lambda$, we can write $\lambda = \frac{c}{\nu}$. Substituting this into the momentum equation gives $p = \frac{h\nu}{c}$.

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