Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

Electrons of mass m with de-Broglie wavelength $\lambda$ fall on the target in an X-ray tube. The cutoff wavelength ($\lambda_0$) of the emitted X-ray is: (2016-II)
$\lambda_0 = \frac{2m^2c^2\lambda^2}{h^2}$
$\lambda_0 = \lambda$
$\lambda_0 = \frac{2mc\lambda^2}{h}$
$\lambda_0 = \frac{2h}{mc}$

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