Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

The de Broglie wavelength of an electron accelerated through a potential difference V is given by $\lambda = \frac{1.227}{\sqrt{V}} nm$. Given $\lambda = 1.227 \times 10^{-2} nm$. Equating the two gives $\frac{1.227}{\sqrt{V}} = 1.227 \times 10^{-2}$, which simplifies to $\sqrt{V} = 10^2$. Squaring both sides gives $V = 10^4 V$.