Photoelectric Effects and deBroglie Equation: Practice Problem & Solution
Monochromatic light of frequency $6.0 \times 10^{14}$ Hz is produced by a laser. The power emitted is $2 \times 10^{-3}$ W. The number of photons emitted, on the average, by the sources per second is: (2007)
Solution Explained:
To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:
Energy of a single photon is $E = h\nu = 6.6 \times 10^{-34} \times 6.0 \times 10^{14} = 39.6 \times 10^{-20} J$. The number of photons emitted per second is $n = \frac{P}{E} = \frac{2 \times 10^{-3}}{39.6 \times 10^{-20}} \approx 0.05 \times 10^{17} = 5 \times 10^{15}$.
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