Time period of cyclotron motion – Rankers Physics

Force Acting on Moving Charges: Practice Problem & Solution

A charged particle is moving on circular path with velocity \(v\) in a uniform magnetic field \(B\). If velocity of the particle and strength of magnetic field is doubled, then time taken to complete one revolution becomes
8 times
4 times
\(\frac{1}{2}\) times
\(\frac{1}{8}\) times

Solution Explained:

To solve this problem, we apply the core principles of Force Acting on Moving Charges. Understanding the underlying formula is key to arriving at the correct answer below:

The time period of revolution in a magnetic field is \[T = \frac{2\pi m}{qB}\]. It is independent of the velocity \(v\) and inversely proportional to \(B\). Thus, doubling \(B\) makes the time period half of its initial value.

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