Rankers Physics

Magnetic Field Due to Straight Current Carrying Wire: Practice Problem & Solution

The magnetic field at center O of the arc in figure is : Magnetic Field Due to Straight Current Carrying Wire diagram: The magnetic field at center O of the
\[\frac{\mu_{0}I}{4\pi\times r}\left[ \sqrt{2} +\pi \right]\]
\[\frac{\mu I}{2\pi r}\left[\frac{\pi}{4}+ \left( \sqrt{2}- 1 \right)\right]\]
\[\frac{\mu_{0}}{2\pi }\times \frac{I}{r}[\sqrt{2}-\pi ]\]
\[\frac{\mu_{0}}{4\pi }\times \frac{I}{r}[\sqrt{2}+\frac{\pi}{4} ]\]

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