Rankers Physics

Magnetic Field Due to Straight Current Carrying Wire: Practice Problem & Solution

A semi-infinite straight conductor carries a current I P is a point at perpendicular distance a from the conductor as shown. The field at P due to the conductor is : Magnetic Field Due to Straight Current Carrying Wire diagram: A semi-infinite straight conductor carries a current I
\[B=\frac{\mu_{0}I}{4\pi a}(1+sin\phi):outwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+cos\phi):outwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+sin\phi):inwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+cos\phi):inwards\]

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Similar Practice Questions

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1. Given below are two statements Statement I : Biot-Savart's law gives us the expression for the magnetic field strength of an infinitesimal current element ($I d \vec{l}$) of the current carrying conductor only. Statement II : Biot-Savart's law is analogous to Coulomb's inverse square law of charge $q$, with the former being related to the field produced by a scalar source, $Id \vec{l}$, while the latter being produced by a vector source, $q$. In light of above statements choose the most appropriate answer from the options given below
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