Magnetic Properties of Matter: Practice Problem & Solution
The magnetic moment of a magnet having dimensions (10 cm × 5 cm × 4 cm) is \(2.5 \text{A m}^2\). The intensity of magnetisation of magnet is
Solution Explained:
To solve this problem, we apply the core principles of Magnetic Properties of Matter. Understanding the underlying formula is key to arriving at the correct answer below:
Intensity of magnetisation \(I = \frac{M}{V}\). Volume \(V = 0.10 \times 0.05 \times 0.04 = 2 \times 10^{-4} \text{m}^3\). So, \(I = \frac{2.5}{2 \times 10^{-4}} = 1.25 \times 10^4 \text{A/m}\).
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