Rankers Physics

Force Acting on Moving Charges: Practice Problem & Solution

A charged particle of mass m, charge q is moving with speed v. It enters a uniform magnetic field acting perpendicular to the plane of paper inwards as shown in Fig. The width of the magnetic field is √3 mv/2qB . Then time taken by charged particle to emerge from the magnetic field is : Force Acting on Moving Charges diagram: A charged particle of mass m, charge q
πm/2qB
πm/3qB
πm/6qB
πm/2√2qB

No solution provided for this question.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. An electron having mass '$m$' and kinetic energy E enter in uniform magnetic field B perpendicularly, then its frequency will be: (2001)
2. Assertion (A): Magnetic force between two charge is generally much smaller than the electric force between them. Reason (R): Speeds of charges are much smaller than the free-space speed of light.  
3. Two very long straight parallel wires carry steady currents i and 2i in opposite directions. The distance between the wires is d. At a certain instant of time a point charge q is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity \(\overrightarrow{v}\) is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is :
4. In crossed electric and magnetic field, the velocity of charged particle which passes undeflected through the region may be (where \(E\) is electric field and \(B\) is magnetic field)
5. A magnetic field: