Rankers Physics

Ampere's Circuital Law: Practice Problem & Solution

A solenoid consists of 100 turns of wire and has a length of 10.0cm. The magnetic field inside the solenoid when it carries a current of 0.500 A will be :
\[6.28\times 10^{-4} T\]
\[6.28\times 10^{-5} T\]
\[3.14\times 10^{-4} T\]
none of these

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Ampere's Circuital Law. Understanding the underlying formula is key to arriving at the correct answer below:

\[ B= \mu_{0}ni \] where n is number of turns per unit length

n= 100/0.1=1000

i=0.5

substituting we get \[ B = 6.28\times 10^{-4} T\]

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Assertion (A): In Ampere's law for magnetostatics \(\oint \vec{B} \cdot d\vec{l} = \mu_0 \sum I_{\text{i}}\) the current outside the Amperian loop is not included on the right side. Reason (R): Magnetic field calculated using Ampere's law is due to inside as well outside the current of closed loop.  
2. Consider six wires coming into or out of the page, all with the same current. Rank the line integral of the magnetic field (from most positive to most negative) taken counter-clockwise around each loop shown.
3. For the hollow thin cylindrical current carrying straight pipe which statement is correct:
4. In a co-axial straight cable, the central conductor and the outer conductor have equal currents in opposite directions. The magnetic induction is zero :
5. Assertion (A): A rectangular current loop is in an arbitrary orientation in an external uniform magnetic field. No work is required to rotate the loop about an axis perpendicular to its plane. Reason (R): All positions represent the same level of energy.