Rankers Physics

Magnetic Properties of Matter: Practice Problem & Solution

16. A bar magnet is oscillating in the Earth's magnetic field with a period $T$. What happens to its period and motion if its mass is quadrupled? (2003)
Motion remains S.H.M. with time period $= \frac{T}{2}$
Motion remains S.H.M with time period $= 2T$
Motion remains S.H.M with time period $= 4T$
Motion remains S.H.M and period remains nearly constant

Solution Explained:

To solve this problem, we apply the core principles of Magnetic Properties of Matter. Understanding the underlying formula is key to arriving at the correct answer below:

Time period is given by $T = 2\pi \sqrt{\frac{I}{MB}}$. Moment of inertia $I$ is directly proportional to mass $m$. If mass is quadrupled, $I$ becomes $4I$.
New period $T' = 2\pi \sqrt{\frac{4I}{MB}} = 2T$. The restoring torque is still $-MB \sin \theta$, so motion remains S.H.M.

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