Rankers Physics

Magnetic Properties of Matter: Practice Problem & Solution

If number of turn, area and current through it is given by $n$, $A$ and $i$ respectively then its magnetic moment will be: (2001)
$niA$
$n^2iA$
$niA^2$
$\frac{ni}{\sqrt{A}}$

Solution Explained:

To solve this problem, we apply the core principles of Magnetic Properties of Matter. Understanding the underlying formula is key to arriving at the correct answer below:

Magnetic dipole moment of a current-carrying coil is the product of number of turns, current, and area, i.e., $M = niA$.

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