Magnetic Properties of Matter: Practice Problem & Solution
A charged particle (charge $q$) is moving in a circle of radius $R$ with uniform speed $v$. The associated magnetic moment $\mu$ is given by: (2007)
Solution Explained:
To solve this problem, we apply the core principles of Magnetic Properties of Matter. Understanding the underlying formula is key to arriving at the correct answer below:
Equivalent current $I = q / T = qv / (2\pi R)$. Magnetic moment $\mu = I A = \frac{qv}{2\pi R} \pi R^2 = \frac{qvR}{2}$.
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