Rankers Physics

Force Acting on Current Carrying Conductor: Practice Problem & Solution

A straight wire of length $0.5\text{ metre}$ and carrying a current of $1.2\text{ ampere}$ is placed in uniform magnetic field of induction $2\text{ tesla}$. The magnetic field is perpendicular to the length of the wire. The force on the wire is: (1992)
$2.4text{ N}$
$1.2text{ N}$
$3.0text{ N}$
$2.0text{ N}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Force Acting on Current Carrying Conductor. Understanding the underlying formula is key to arriving at the correct answer below:

The magnetic force on a current-carrying wire is given by $F = I l B sintheta$.
Substituting $I = 1.2text{ A}$, $l = 0.5text{ m}$, $B = 2text{ T}$, and $theta = 90^circ$ yields $F = 1.2text{ N}$.

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