Rankers Physics

Force Acting on Current Carrying Conductor: Practice Problem & Solution

Two long parallel wires are at a distance of $1\text{ m}$. If both of them carry one ampere of current in same direction, then the force of attraction on unit length of the wires will be: (1998)
$2 \times 10^{-7}\text{ N/m}$
$4 \times 10^{-7}\text{ N/m}$
$8 \times 10^{-7}\text{ N/m}$
$10^{-7}\text{ N/m}$

Solution Explained:

To solve this problem, we apply the core principles of Force Acting on Current Carrying Conductor. Understanding the underlying formula is key to arriving at the correct answer below:

The force per unit length between two parallel current-carrying wires is $\frac{F}{l} = \frac{mu_0 I_1 I_2}{2\pi d}$.
Substituting $I_1 = 1\text{ A}$, $I_2 = 1\text{ A}$, and $d = 1\text{ m}$ results in $2 \times 10^{-7}\text{ N/m}$.

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