Force Acting on Moving Charges: Practice Problem & Solution
The magnetic force acting on a charged particle of charge $-2\text{ }\mu\text{C}$ in a magnetic field of $2\text{ T}$ acting in $y$ direction, when the particle velocity is $(2\hat{i} + 3\hat{j}) \times 10^6\text{ ms}^{-1}$, is: (2009)
Solution Explained:
To solve this problem, we apply the core principles of Force Acting on Moving Charges. Understanding the underlying formula is key to arriving at the correct answer below:
Using $\vec{F} = q(\vec{v} \times \vec{B})$, substituting $q = -2 \times 10^{-6}\text{ C}$, $\vec{v} = (2\hat{i} + 3\hat{j}) \times 10^6\text{ ms}^{-1}$, and $\vec{B} = 2\hat{j}\text{ T}$ yields $-8\hat{k}\text{ N}$, i.e., $8\text{ N}$ in $-z$ direction.
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